Pin state is low or 0, switch is closed (pull-up resistor)ģ.3.1.2 Pins as Inputs, Internal Pull-up Resistors Pin state is high or 1, switch is open (pull-up resistor) Read Arduino MEGA 2560 pin 2 state with pull-up resistor. Pin state is low or 0, switch is open (pull-down resistor)ĭigitalWrite(LED_BUILTIN, LOW) // Switch L LED offģ.3.1.2 Pins as Inputs, Pull-up Resistor Pin state is high or 1, switch is closed (pull-down resistor)ĭigitalWrite(LED_BUILTIN, HIGH) // Switch L LED on Read Arduino MEGA 2560 pin 2 state with pull-down resistor. Serial.print(voltage) // Display voltageĢ.7.5.4 Analog In Pins Used as Digital I/O, Īrduino MEGA 2560 analog pin A0 used as a digital output pin.ģ.3.1.2 Pins as Inputs, Pull-down Resistor Int sensorValue = analogRead(A0) // Read ADC valueįloat voltage = (5.0 / 1024.0) * (float)sensorValue // Calculate voltage PinMode(MY_LED, OUTPUT) // Configure digital pin as an output pinĭigitalWrite(MY_LED, HIGH) // Set pin voltage to 5V on a MEGA 2560ĭigitalWrite(MY_LED, LOW) // Set pin voltage to 0V or GNDĪrduino MEGA 2560 PWM on pin 3 with 50% duty cycle.Ģ.7.5.3 Calculating Analog In Voltage, Ĭalculating analog input voltage on Arduino MEGA 2560 A0 pin. PinMode(12, OUTPUT) // Configure digital pin 12 as an output pinĭigitalWrite(12, HIGH) // Set pin 12 voltage to 5V on a MEGA 2560ĭigitalWrite(12, LOW) // Set pin 12 voltage to 0V or GNDĭefining a pin with a user friendly name. PinMode(LED_BUILTIN, OUTPUT) // Configure L LED pin as outputĭigitalWrite(LED_BUILTIN, HIGH) // Switch L LED ONĭigitalWrite(LED_BUILTIN, LOW) // Switch L LED OFFĭelay(200) // Leave L LED OFF for periodĪrduino MEGA 2560 pin 12 configured as an output and driven high and low. This page has been left to support those readers who bought the older book, which is no longer available. This connector starts with 16, 15, 1, 2, 3, and so on FROM RIGHT TO LEFT.The Arduino MEGA 2560 Hardware Manual has been replaced by the newer full color revised and updated Ultimate Arduino MEGA 2560 Hardware Manual. Well after searching a lot, i found that this is an oddball LCD with a non standard 16 pin connector. Your PDF document can't be opened (here). This will very likely give us some clue as to where pin 1 is. Please show a clear photo from top and bottom of your display module, showing the connection pins without anything connected to it. I suspect it really is number 14 and in that case all bets are off. If pin numbering would be standard, these pins would be pins 0 and -1 and that makes no sense at all.Īre you sure your pin number 1 is number 1 and not number 14 ? These pads are at the right hand side of your display. We all were looking at the pot and it's wiring.īut your last photo shows something that wasn't directly visible to us, you have 2 more solderpads left. I'm sorry, but it is not wired correctly. Just if it's a mistake that I don't thinks so. It's on the datasheet and also on the board written. I just wan't to be sure that Is a faulty LCD before buying a new photo's don't show how the resistor is wired up so that doesn't really help. So the red wire is connected to +5V., blue to GND and white to V0 and that's it. I am thinking also that maybe I did something wrong at the beggining that have damaged the LCD.Īnyway here it is the photo of how I have connected the Potentiometer (I have connected without soldering just to see how I did it). Reconfirm your wiring and if you are sure it is correct, try an other display (which you probably don't have around right now.). Your picture shows the lines somewhere in the center of the screen and not at the first edge. I can't display anything else than these lines, but they are all over the display.Īnother display works OK here so it can't be the wiring, but maybe i did something wrong the first time, i don't know. That way you can easily move pins around.īut i have to tell you, i saw very similar patterns on the display i had. I would (and did that while playing aroud with a display for the first time) use a breadboard instead of a veroboard. Your discription in the post above however is correct. I'd have to guess and would say that it is indeed wired incorrectly but can't be sure. I replied in the thread you created by accident (click), your problem is very different from aescom's problem and you are disturbing the discussion of his problem, most likely without that photo's don't show how the resistor is wired up so that doesn't really help.
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